3w^2+39w+90=0

Solution for 3w^2+39w+90=0 equation:

3w^2+39w+90=0

a = 3; b = 39; c = +90;
Δ = b2-4ac
Δ = 392-4·3·90
Δ = 441
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{441}=21$
$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(39)-21}{2*3}=\frac{-60}{6}
=-10
$
$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(39)+21}{2*3}=\frac{-18}{6}
=-3
$